(x^2-2x+1)/(x+1)=0

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Solution for (x^2-2x+1)/(x+1)=0 equation: 



(x^2-2x+1)/(x+1)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



We multiply all the terms by the denominator


(x^2-2x+1)=0

We get rid of parentheses

x^2-2x+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{2}=1$

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